What is maclaurin 1/(\sqrt[3]{2x+1)} ?

The answer to maclaurin 1/(\sqrt[3]{2x+1)} is 1-2/3 x+8/9 x^2-112/81 x^3+560/243 x^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

maclaurin 1/(\sqrt[3]{2x+1)}

maclaurin

1 - \frac{2}{3} x + \frac{8}{9} x^{2} - \frac{112}{81} x^{3} + \frac{560}{243} x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

Evaluate Derivatives

= 1 + \frac{- \frac{2}{3}}{1 !} x + \frac{\frac{16}{9}}{2 !} x^{2} + \frac{- \frac{224}{27}}{3 !} x^{3} + \frac{\frac{4480}{81}}{4 !} x^{4} + \dots

Refine

= 1 - \frac{2}{3} x + \frac{8}{9} x^{2} - \frac{112}{81} x^{3} + \frac{560}{243} x^{4} + \dots

What is maclaurin 1/(\sqrt[3]{2x+1)} ?
The answer to maclaurin 1/(\sqrt[3]{2x+1)} is 1-2/3 x+8/9 x^2-112/81 x^3+560/243 x^4+\ldots