What is the tangent of f(x)=2x^3-4x^2,\at x=1 ?

The tangent of f(x)=2x^3-4x^2,\at x=1 is y=-2x

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tangent of f(x)=2x^3-4x^2,\at x=1

tangent of

f (x) = 2 x^{3} - 4 x^{2}, at x = 1

y = - 2 x

Solution steps

Find the tangent point:

(1, - 2)

Find the slope of

f (x) = 2 x^{3} - 4 x^{2} : \frac{df ( x )}{d x} = 6 x^{2} - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(1, - 2) : y = - 2 x

y = - 2 x

What is the tangent of f(x)=2x^3-4x^2,\at x=1 ?
The tangent of f(x)=2x^3-4x^2,\at x=1 is y=-2x