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Popular Calculus >

area y=x^3,y=x^2+x

Solution

area

y = x^{3}, y = x^{2} + x

Solution

\frac{13}{12}

+1

Decimal

1.08333 \dots

Solution steps

Apply the area formula:

\int_{\frac{1 - 5}{2}}^{\frac{1 + 5}{2}} x^{3} - (x^{2} + x) d x

Solve

\int_{\frac{1 - 5}{2}}^{\frac{1 + 5}{2}} x^{3} - (x^{2} + x) d x : \frac{13}{12}

The area is:

= \frac{13}{12}

Graph

Popular Examples

integral of 4x+1/x

integral of 2/(2+x^2)

(dy)/(dt)+y/t =2

(\partial)/(\partial y)((2x)/(y^3))

Frequently Asked Questions (FAQ)

What is area y=x^3,y=x^2+x ?
The answer to area y=x^3,y=x^2+x is 13/12