What is the limit as x approaches 2 of 2x^2+4x+a ?

The limit as x approaches 2 of 2x^2+4x+a is a+16

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limit as x approaches 2 of 2x^2+4x+a

x \to 2 lim (2 x^{2} + 4 x + a)

a + 16

Solution steps

x \to 2 lim (2 x^{2} + 4 x + a)

Plug in the value

x = 2

= 2 \cdot 2^{2} + 4 \cdot 2 + a

Simplify

2 \cdot 2^{2} + 4 \cdot 2 + a : a + 16

= a + 16

What is the limit as x approaches 2 of 2x^2+4x+a ?
The limit as x approaches 2 of 2x^2+4x+a is a+16