What is the derivative of 120x^3-180x^2+60 ?

The derivative of 120x^3-180x^2+60 is 360x^2-360x

What is the first derivative of 120x^3-180x^2+60 ?

The first derivative of 120x^3-180x^2+60 is 360x^2-360x

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\frac{d}{d x} (120 x^{3} - 180 x^{2} + 60)

360 x^{2} - 360 x

Solution steps

\frac{d}{d x} (120 x^{3} - 180 x^{2} + 60)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (120 x^{3}) - \frac{d}{d x} (180 x^{2}) + \frac{d}{d x} (60)

\frac{d}{d x} (120 x^{3}) = 360 x^{2}

\frac{d}{d x} (180 x^{2}) = 360 x

\frac{d}{d x} (60) = 0

= 360 x^{2} - 360 x + 0

Simplify

= 360 x^{2} - 360 x

What is the derivative of 120x^3-180x^2+60 ?
The derivative of 120x^3-180x^2+60 is 360x^2-360x
What is the first derivative of 120x^3-180x^2+60 ?
The first derivative of 120x^3-180x^2+60 is 360x^2-360x