What is the integral of ((ln(x))/(x^2)) ?

The integral of ((ln(x))/(x^2)) is -(ln(x))/x-1/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of ((ln(x))/(x^2))

\int (\frac{ln ( x )}{x ^{2}}) d x

- \frac{ln ( x )}{x} - \frac{1}{x} + C

Solution steps

\int \frac{ln ( x )}{x ^{2}} d x

Apply Integration By Parts

= - \frac{ln ( x )}{x} - \int - \frac{1}{x ^{2}} d x

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= - \frac{ln ( x )}{x} - \frac{1}{x}

Add a constant to the solution

= - \frac{ln ( x )}{x} - \frac{1}{x} + C

What is the integral of ((ln(x))/(x^2)) ?
The integral of ((ln(x))/(x^2)) is -(ln(x))/x-1/x+C