What is the solution for (dx)/(dt)=2x^2-3x ?

The solution for (dx)/(dt)=2x^2-3x is x=-(3e^{-3t-3c_{1}})/(2(1-e^{-3(t+c_{1))})}

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(dx)/(dt)=2x^2-3x

\frac{d x}{d t} = 2 x^{2} - 3 x

x = - \frac{3 e ^{- 3 t - 3 c_{1}}}{2 ( 1 - e ^{- 3 (t + c_{1})} )}

Solution steps

\frac{d x}{d t} = 2 x^{2} - 3 x

Solve separable ODE:

x = - \frac{3 e ^{- 3 t - 3 c_{1}}}{2 ( 1 - e ^{- 3 (t + c_{1})} )}

x = - \frac{3 e ^{- 3 t - 3 c_{1}}}{2 ( 1 - e ^{- 3 (t + c_{1})} )}

What is the solution for (dx)/(dt)=2x^2-3x ?
The solution for (dx)/(dt)=2x^2-3x is x=-(3e^{-3t-3c_{1}})/(2(1-e^{-3(t+c_{1))})}