What is the integral of (-5)/((x+2)^2) ?

The integral of (-5)/((x+2)^2) is 5/(x+2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (-5)/((x+2)^2)

\int \frac{- 5}{( x + 2 ) ^{2}} d x

\frac{5}{x + 2} + C

Solution steps

\int \frac{- 5}{( x + 2 ) ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 5 \cdot \int \frac{1}{( x + 2 ) ^{2}} d x

Apply u-substitution

= - 5 \cdot \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= - 5 (- \frac{1}{u})

Substitute back

u = x + 2

= - 5 (- \frac{1}{x + 2})

Simplify

- 5 (- \frac{1}{x + 2}) : \frac{5}{x + 2}

= \frac{5}{x + 2}

Add a constant to the solution

= \frac{5}{x + 2} + C

What is the integral of (-5)/((x+2)^2) ?
The integral of (-5)/((x+2)^2) is 5/(x+2)+C