What is the domain of (sqrt(2x-9))/(2x+9) ?

The domain of (sqrt(2x-9))/(2x+9) is x>= 9/2

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domain of (sqrt(2x-9))/(2x+9)

domain

\frac{2 x - 9}{2 x + 9}

x \geq \frac{9}{2}

Interval Notation

[\frac{9}{2}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq \frac{9}{2}

Find undefined (singularity) points:

x = - \frac{9}{2}

Combine real regions and undefined points for final function domain

x \geq \frac{9}{2}

What is the domain of (sqrt(2x-9))/(2x+9) ?
The domain of (sqrt(2x-9))/(2x+9) is x>= 9/2