What is the domain of q(x)=(x-3)/(x^2+x-12) ?

The domain of q(x)=(x-3)/(x^2+x-12) is x 3

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domain of q(x)=(x-3)/(x^2+x-12)

domain

q (x) = \frac{x - 3}{x ^{2} + x - 12}

x < - 4 or - 4 < x < 3 or x > 3

Interval Notation

(- \infty, - 4) \cup (- 4, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = - 4

The function domain

x < - 4 or - 4 < x < 3 or x > 3

What is the domain of q(x)=(x-3)/(x^2+x-12) ?
The domain of q(x)=(x-3)/(x^2+x-12) is x<-4\lor-4<x<3\lor x>3