定义域 f(x)=(x^2-4)/(2+sqrt(x-1))

解答

定义域

f (x) = \frac{x ^{2} - 4}{2 + x - 1}

x \geq 1

间隔符号

[1, \infty)

求解步骤

对于根式找到非负值:

x \geq 1

函数定义域

x \geq 1

d o main f (x) = \frac{x ^{2} + 2 x - 3}{x ^{2} + 5 x + 6}

d o main 7 x^{2} + 8

d o main f (x) = x^{(3)} - 7 x^{(2)} + 10 x

d o main f (x) = \frac{x + 5}{x - 9}

d o main f (x) = 4 x^{2} + 3