What is the domain of f(x)=sqrt((x+4)(x+5)(x+8)) ?

The domain of f(x)=sqrt((x+4)(x+5)(x+8)) is -8 =-4

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domain of f(x)=sqrt((x+4)(x+5)(x+8))

domain

f (x) = (x + 4) (x + 5) (x + 8)

- 8 \leq x \leq - 5 or x \geq - 4

Interval Notation

[- 8, - 5] \cup [- 4, \infty)

Solution steps

Find non-negative values for radicals:

- 8 \leq x \leq - 5 or x \geq - 4

The function domain

- 8 \leq x \leq - 5 or x \geq - 4

What is the domain of f(x)=sqrt((x+4)(x+5)(x+8)) ?
The domain of f(x)=sqrt((x+4)(x+5)(x+8)) is -8<= x<=-5\lor x>=-4