定义域 f(x)=(4x(x-6))/(2x^2-5x-3)

解答

定义域

f (x) = \frac{4 x ( x - 6 )}{2 x ^{2} - 5 x - 3}

x < - \frac{1}{2} or - \frac{1}{2} < x < 3 or x > 3

间隔符号

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, 3) \cup (3, \infty)

求解步骤

找到无定义的点（奇点）:

x = 3, x = - \frac{1}{2}

函数定义域

x < - \frac{1}{2} or - \frac{1}{2} < x < 3 or x > 3

d o main \frac{1}{3} x

d o main lo g_{10} (\frac{x + 6}{x ^{2} - 4})

d o main y = x x^{2} - 2

d o main f (x) = 0 x - 285000

d o main y = \frac{( x + 7 ) ^{2}}{6 x - 2}