extreme f(x)=xe^{6x}

Lösung

extrempunkte

f (x) = x e^{6 x}

Minimum (- \frac{1}{6}, - \frac{1}{6 e})

Schritte zur Lösung

f^{'} (x) = e^{6 x} + 6 e^{6 x} x

Intervalle finden:

Absteigend

: - \infty < x < - \frac{1}{6},

Ansteigend

: - \frac{1}{6} < x < \infty

Stecke

x = - \frac{1}{6}

x e^{6 x} : - \frac{1}{6 e}

Minimum (- \frac{1}{6}, - \frac{1}{6 e})

e x t re m e f (x, y) = e^{- x^{2} - y^{2}} (x^{2} + 2 y^{2})

e x t re m e f (x) = x^{4} - 8 x^{3} + 22 x^{2} - 24 x

e x t re m e f (x) = - \frac{5 x ^{3}}{3} + 10 x^{2} + 25 x

e x t re m e f (x) = 8 - 3 x - 6 x^{2}

e x t re m e cos (t)