extreme x^3-x^2-8x+8

Lösung

extrempunkte

x^{3} - x^{2} - 8 x + 8

Maximum (- \frac{4}{3}, \frac{392}{27}), Minimum (2, - 4)

Schritte zur Lösung

f^{'} (x) = 3 x^{2} - 2 x - 8

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{4}{3},

Absteigend

: - \frac{4}{3} < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = - \frac{4}{3}

x^{3} - x^{2} - 8 x + 8 : \frac{392}{27}

Maximum (- \frac{4}{3}, \frac{392}{27})

Stecke

x = 2

x^{3} - x^{2} - 8 x + 8 : - 4

Minimum (2, - 4)

Maximum (- \frac{4}{3}, \frac{392}{27}), Minimum (2, - 4)

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e x t re m e f (x) = 4 x^{2} - 32 ln (x)

e x t re m e y = - 6 - z^{2} - x^{2}

e x t re m e f (x, y) = - x^{2} - 2 y^{2} + x y + x + 3 y

e x t re m e f (x) = - \frac{2}{3} x^{3} + 2 x^{2} + 6 x - 50