extreme f(x)=5x^2-x-2

Lösung

extrempunkte

f (x) = 5 x^{2} - x - 2

Minimum (\frac{1}{10}, - \frac{41}{20})

Schritte zur Lösung

f^{'} (x) = 10 x - 1

Intervalle finden:

Absteigend

: - \infty < x < \frac{1}{10},

Ansteigend

: \frac{1}{10} < x < \infty

Stecke

x = \frac{1}{10}

5 x^{2} - x - 2 : - \frac{41}{20}

Minimum (\frac{1}{10}, - \frac{41}{20})

e x t re m e f (x) = x^{3} - 6 x^{2} + 5 [- 3.5]

e x t re m e f (x) = 3 3 x^{2} - 2 x

e x t re m e f (x) = \frac{x ^{4}}{4} - \frac{x ^{3}}{3} - 3 x^{2}

e x t re m e f (x) = 2 x + \frac{20}{x}

e x t re m e f (x, y) = x^{3} + y^{2} - 6 x y - 29 x + 18 y + 20