extreme 2x^3-2x^2-2x+9

Lösung

extrempunkte

2 x^{3} - 2 x^{2} - 2 x + 9

Maximum (- \frac{1}{3}, \frac{253}{27}), Minimum (1, 7)

Schritte zur Lösung

f^{'} (x) = 6 x^{2} - 4 x - 2

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{1}{3},

Absteigend

: - \frac{1}{3} < x < 1,

Ansteigend

: 1 < x < \infty

Stecke

x = - \frac{1}{3}

2 x^{3} - 2 x^{2} - 2 x + 9 : \frac{253}{27}

Maximum (- \frac{1}{3}, \frac{253}{27})

Stecke

x = 1

2 x^{3} - 2 x^{2} - 2 x + 9 : 7

Minimum (1, 7)

Maximum (- \frac{1}{3}, \frac{253}{27}), Minimum (1, 7)

e x t re m e f (x, y) = x^{2} - 4 x + y^{2} - 6 y - 2

e x t re m e f (x) = 4 x^{3} - x^{2} + 9

e x t re m e x^{2} - 6 x + 12

e x t re m e f (x) = \cdot f (y) - f (x, y) (x y) = 3 x + 3 y + 6

e x t re m e f (x) = x^{2} - 7 x + 10