de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Funktionen >

extreme f(x)=x^2+(200)/x

Lösung

extrempunkte

f (x) = x^{2} + \frac{200}{x}

Lösung

Minimum (3100, 10 0^{\frac{2}{3}} + \frac{200}{3 100})

Schritte zur Lösung

f^{'} (x) = 2 x - \frac{200}{x ^{2}}

Intervalle finden:

Absteigend

: - \infty < x < 0,

Absteigend

: 0 < x < 3100,

Ansteigend

: 3100 < x < \infty

Stecke

x = 3100

in

x^{2} + \frac{200}{x} : 10 0^{\frac{2}{3}} + \frac{200}{3 100}

Minimum (3100, 10 0^{\frac{2}{3}} + \frac{200}{3 100})

Graph

Beliebte Beispiele

extreme-0.1t^2+0.8t+98.8,0<= t>= 8

e x t re m e - 0.1 t^{2} + 0.8 t + 98.8, 0 \leq t \geq 8

extreme x^8ln(x)

e x t re m e x^{8} ln (x)

extreme f(x)=x^6+4x^5+10

e x t re m e f (x) = x^{6} + 4 x^{5} + 10

extreme F(x,y)=2x^5+x^3y^2+6xy^4

e x t re m e F (x, y) = 2 x^{5} + x^{3} y^{2} + 6 x y^{4}

extreme f(x)=(9x)/(x^2+9)

e x t re m e f (x) = \frac{9 x}{x ^{2} + 9}