extreme h(x)=2(x-5)^3

Lösung

extrempunkte

h (x) = 2 (x - 5)^{3}

Sattel (5, 0)

Schritte zur Lösung

f^{'} (x) = 6 (x - 5)^{2}

Intervalle finden:

Ansteigend

: - \infty < x < 5,

Ansteigend

: 5 < x < \infty

Stecke

x = 5

2 (x - 5)^{3} : 0

Sattel (5, 0)

e x t re m e f (x, y) = x^{2} + 2 y^{2} - x y + 3 x + 2 y

e x t re m e f (x) = - 5 x^{3} + 15 x + 6

e x t re m e f (x, y) = (x - 5) (30 - 6 x + 4 y) + (y - 12) (80 + 8 x - 7 y)

e x t re m e f (x) = - 0.001 x^{2} + 3.4 x - 40

e x t re m e \frac{sin ( 5 x )}{sin ^{5} ( x )}