extreme f(x)=-5x+2ln(2x)

解答

极值点

f (x) = - 5 x + 2 ln (2 x)

极大值 (\frac{2}{5}, - 2 + 2 ln (\frac{4}{5}))

求解步骤

f^{'} (x) = - 5 + \frac{2}{x}

Find intervals:

递增

: 0 < x < \frac{2}{5},

递减

: \frac{2}{5} < x < \infty

将

x = \frac{2}{5}

代入

- 5 x + 2 ln (2 x) : - 2 + 2 ln (\frac{4}{5})

极大值 (\frac{2}{5}, - 2 + 2 ln (\frac{4}{5}))

e x t re m e \frac{x + 3}{x ^{2} - 2 x - 15}

e x t re m e f (x, y) = - (x + 1) 2 - (y + x) 2

e x t re m e f (x) = 2 x^{2} - 3 x - 5

e x t re m e f (x) = 3 x^{3} - 2 x^{4}

e x t re m e f (x) = 340 x^{2} - 2040 x^{3}