extreme f(x)=(4860)/x+11x+710272

Lösung

extrempunkte

f (x) = \frac{4860}{x} + 11 x + 710272

Maximum (- \frac{18 15}{11}, - 36165 + 710272), Minimum (\frac{18 15}{11}, 36165 + 710272)

Schritte zur Lösung

f^{'} (x) = - \frac{4860}{x ^{2}} + 11

Intervalle finden:

Ansteigend

: - \infty < x < - \frac{18 15}{11},

Absteigend

: - \frac{18 15}{11} < x < 0,

Absteigend

: 0 < x < \frac{18 15}{11},

Ansteigend

: \frac{18 15}{11} < x < \infty

Stecke

x = - \frac{18 15}{11}

\frac{4860}{x} + 11 x + 710272 : - 36165 + 710272

Maximum (- \frac{18 15}{11}, - 36165 + 710272)

Stecke

x = \frac{18 15}{11}

\frac{4860}{x} + 11 x + 710272 : 36165 + 710272

Minimum (\frac{18 15}{11}, 36165 + 710272)

Maximum (- \frac{18 15}{11}, - 36165 + 710272), Minimum (\frac{18 15}{11}, 36165 + 710272)

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