extreme f(x)=x^2+9x-2

解答

极值点

f (x) = x^{2} + 9 x - 2

极小值 (- \frac{9}{2}, - \frac{89}{4})

求解步骤

f^{'} (x) = 2 x + 9

Find intervals:

递减

: - \infty < x < - \frac{9}{2},

递增

: - \frac{9}{2} < x < \infty

将

x = - \frac{9}{2}

代入

x^{2} + 9 x - 2 : - \frac{89}{4}

极小值 (- \frac{9}{2}, - \frac{89}{4})