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midpoint
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domain of f(x)=(x^3)/3periodicity of f(x)=sin(x/6)range of (12-x-x^2)/(|x-3|)inverse of f(x)=2(x-1)^2+7critical f(x)=2(3-x)
Frequently Asked Questions (FAQ)
What is the midpoint (-1,1),(-10,-5) ?
The midpoint (-1,1),(-10,-5) is (-11/2 ,-2)