What is the asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) ?

The asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) is Vertical: x= 4/3 ,Horizontal: y= 1/3

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asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4)

asymptotes

f (x) = \frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4}

Vertical : x = \frac{4}{3}, Horizontal : y = \frac{1}{3}

Solution steps

Vertical asymptotes of

\frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4} : x = \frac{4}{3}

Horizontal Asymptotes of

\frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4} : y = \frac{1}{3}

Slant Asymptotes of

\frac{x ^{2} + 2 x + 1}{3 x ^{2} - x - 4} :

None

Vertical : x = \frac{4}{3}, Horizontal : y = \frac{1}{3}

What is the asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) ?
The asymptotes of f(x)=(x^2+2x+1)/(3x^2-x-4) is Vertical: x= 4/3 ,Horizontal: y= 1/3