What is the critical f(x)=x^2(x^2-4) ?

The critical f(x)=x^2(x^2-4) is x=-sqrt(2),x=0,x=sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

critical f(x)=x^2(x^2-4)

critical points

f (x) = x^{2} (x^{2} - 4)

x = - 2, x = 0, x = 2

Solution steps

x^{2} (x^{2} - 4)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{2} (x^{2} - 4) : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

What is the critical f(x)=x^2(x^2-4) ?
The critical f(x)=x^2(x^2-4) is x=-sqrt(2),x=0,x=sqrt(2)