monotone f(x)=-x^4-4x^3+8x-1

Lösung

monotone intervalle

f (x) = - x^{4} - 4 x^{3} + 8 x - 1

Ansteigend : - \infty < x < - 1 - 3, Absteigend : - 1 - 3 < x < - 1, Ansteigend : - 1 < x < - 1 + 3, Absteigend : - 1 + 3 < x < \infty

Schritte zur Lösung

f^{'} (x) = - 4 x^{3} - 12 x^{2} + 8

Intervalle finden:

Ansteigend

: - \infty < x < - 1 - 3,

Absteigend

: - 1 - 3 < x < - 1,

Ansteigend

: - 1 < x < - 1 + 3,

Absteigend

: - 1 + 3 < x < \infty

Ansteigend : - \infty < x < - 1 - 3, Absteigend : - 1 - 3 < x < - 1, Ansteigend : - 1 < x < - 1 + 3, Absteigend : - 1 + 3 < x < \infty

d o main f (x) = 15 - x

a sy m pt o t es f (x) = \frac{3}{x + 5}

s l o p e in t erce pt - 7 y = 8 x - 3

d o main f (x) = \frac{3 x}{x + 5}

in v erse \frac{x}{x + 9}