What is the critical f(x)=x^2+(16)/x ?

The critical f(x)=x^2+(16)/x is x=2

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critical f(x)=x^2+(16)/x

critical points

f (x) = x^{2} + \frac{16}{x}

x = 2

Solution steps

x^{2} + \frac{16}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} + \frac{16}{x} : x < 0 or x > 0

x^{2} + \frac{16}{x}

is not defined at

x = 0

, therefore:

x = 2