What is the extreme f(x)=x^2+((26-2x)^2)/9 ?

The extreme f(x)=x^2+((26-2x)^2)/9 is Minimum(4,52)

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extreme f(x)=x^2+((26-2x)^2)/9

extreme points

f (x) = x^{2} + \frac{( 26 - 2 x ) ^{2}}{9}

Minimum (4, 52)

Solution steps

f^{'} (x) = \frac{26 ( x - 4 )}{9}

Find intervals:

Decreasing

: - \infty < x < 4,

Increasing

: 4 < x < \infty

Plug

x = 4

into

x^{2} + \frac{( 26 - 2 x ) ^{2}}{9} : 52

Minimum (4, 52)

What is the extreme f(x)=x^2+((26-2x)^2)/9 ?
The extreme f(x)=x^2+((26-2x)^2)/9 is Minimum(4,52)