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Popular Functions >

extreme f(x)=x^2+12x+11

Solution

extreme points

f (x) = x^{2} + 12 x + 11

Solution

Minimum (- 6, - 25)

Solution steps

f^{'} (x) = 2 x + 12

Find intervals:

Decreasing

: - \infty < x < - 6,

Increasing

: - 6 < x < \infty

Plug

x = - 6

into

x^{2} + 12 x + 11 : - 25

Minimum (- 6, - 25)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+12x+11 ?
The extreme f(x)=x^2+12x+11 is Minimum(-6,-25)