What is the extreme f(x)=8x^3-6x+4 ?

The extreme f(x)=8x^3-6x+4 is Maximum(-1/2 ,6),Minimum(1/2 ,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

extreme f(x)=8x^3-6x+4

extreme points

f (x) = 8 x^{3} - 6 x + 4

Maximum (- \frac{1}{2}, 6), Minimum (\frac{1}{2}, 2)

Solution steps

f^{'} (x) = 24 x^{2} - 6

Find intervals:

Increasing

: - \infty < x < - \frac{1}{2},

Decreasing

: - \frac{1}{2} < x < \frac{1}{2},

Increasing

: \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

8 x^{3} - 6 x + 4 : 6

Maximum (- \frac{1}{2}, 6)

Plug

x = \frac{1}{2}

into

8 x^{3} - 6 x + 4 : 2

Minimum (\frac{1}{2}, 2)

Maximum (- \frac{1}{2}, 6), Minimum (\frac{1}{2}, 2)

What is the extreme f(x)=8x^3-6x+4 ?
The extreme f(x)=8x^3-6x+4 is Maximum(-1/2 ,6),Minimum(1/2 ,2)