en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Functions >

range of 2x^2-x+4

Solution

range

2 x^{2} - x + 4

Solution

f (x) \geq \frac{31}{8}

+1

Interval Notation

[\frac{31}{8}, \infty)

Solution steps

Vertex of

2 x^{2} - x + 4 :

Minimum

(\frac{1}{4}, \frac{31}{8})

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (\frac{1}{4}, \frac{31}{8})

f (x) \geq \frac{31}{8}

Graph

Popular Examples

inverse of f(x)=(x^5)/6+7

slope of 6x+3y=2

domain of f(x)=\sqrt[3]{x+8}

parallel y=-6x+8,(7,-3)

domain of f(x)= 1/(\sqrt[4]{x^2-8x)}

Frequently Asked Questions (FAQ)

What is the range of 2x^2-x+4 ?
The range of 2x^2-x+4 is f(x)>= 31/8