What is the domain of f(x)=sqrt((x^2-16)(x^2-9)) ?

The domain of f(x)=sqrt((x^2-16)(x^2-9)) is x = 4

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domain of f(x)=sqrt((x^2-16)(x^2-9))

domain

f (x) = (x^{2} - 16) (x^{2} - 9)

x \leq - 4 or - 3 \leq x \leq 3 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [- 3, 3] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or - 3 \leq x \leq 3 or x \geq 4

The function domain

x \leq - 4 or - 3 \leq x \leq 3 or x \geq 4

What is the domain of f(x)=sqrt((x^2-16)(x^2-9)) ?
The domain of f(x)=sqrt((x^2-16)(x^2-9)) is x<=-4\lor-3<= x<= 3\lor x>= 4