What is the inverse of (x^2-16)/(8x^2) ?

The inverse of (x^2-16)/(8x^2) is sqrt(-(16)/(8x-1)),-sqrt(-(16)/(8x-1))

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inverse of (x^2-16)/(8x^2)

inverse

\frac{x ^{2} - 16}{8 x ^{2}}

- \frac{16}{8 x - 1}, - - \frac{16}{8 x - 1}

Solution steps

y = \frac{x ^{2} - 16}{8 x ^{2}}

Replace

x

with

y

x = \frac{y ^{2} - 16}{8 y ^{2}}

Solve for

y, x = \frac{y ^{2} - 16}{8 y ^{2}}

- \frac{16}{8 x - 1}, - - \frac{16}{8 x - 1}

What is the inverse of (x^2-16)/(8x^2) ?
The inverse of (x^2-16)/(8x^2) is sqrt(-(16)/(8x-1)),-sqrt(-(16)/(8x-1))