What is the shift f(x)=-cos(1/2 (x+pi/2)) ?

The shift f(x)=-cos(1/2 (x+pi/2)) is Phase:-pi/2 , Vertical:0

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shift f(x)=-cos(1/2 (x+pi/2))

shift

f (x) = - cos (\frac{1}{2} (x + \frac{π}{2}))

Phase : - \frac{π}{2}, Vertical : 0

Solution steps

f (x) = - cos (\frac{1}{2} (x + \frac{π}{2}))

g (B x - C) = cos (\frac{1}{2} (x + \frac{π}{2})), B = \frac{1}{2}, C = - \frac{π}{4}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{4}}{\frac{1}{2}}

- \frac{π}{2}

The vertical shift

D

0

0

What is the shift f(x)=-cos(1/2 (x+pi/2)) ?
The shift f(x)=-cos(1/2 (x+pi/2)) is Phase:-pi/2 , Vertical:0