What is the critical f(x)=(x-6)/(x+2) ?

The critical f(x)=(x-6)/(x+2) is None

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critical f(x)=(x-6)/(x+2)

critical points

f (x) = \frac{x - 6}{x + 2}

None

Solution steps

\frac{x - 6}{x + 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 6}{x + 2} : x < - 2 or x > - 2

\frac{x - 6}{x + 2}

is not defined at

x = - 2

, therefore:

None