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Popular Functions >

range of-x^2+8x-12

Solution

range

- x^{2} + 8 x - 12

Solution

f (x) \leq 4

+1

Interval Notation

(- \infty, 4]

Solution steps

Vertex of

- x^{2} + 8 x - 12 :

Maximum

(4, 4)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = - 1,

Vertex

(x_{v}, y_{v}) = (4, 4)

f (x) \leq 4

Graph

Popular Examples

domain of x^2-x-20

inverse of f(x)=2-5x^2

inverse of y=5+sqrt(5+x)

critical f(x)=7x^3-3x^2+7

domain of f(x)=(x-7)/((x-3)(x+2))

Frequently Asked Questions (FAQ)

What is the range of-x^2+8x-12 ?
The range of-x^2+8x-12 is f(x)<= 4