What is the extreme f(x)=-0.1x^2+1.2x+98.6 ?

The extreme f(x)=-0.1x^2+1.2x+98.6 is Maximum(6,102.2)

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extreme f(x)=-0.1x^2+1.2x+98.6

extreme points

f (x) = - 0.1 x^{2} + 1.2 x + 98.6

Maximum (6, 102.2)

Solution steps

f^{'} (x) = - 0.2 x + 1.2

Find intervals:

Increasing

: - \infty < x < 6,

Decreasing

: 6 < x < \infty

Plug

x = 6

into

- 0.1 x^{2} + 1.2 x + 98.6 : 102.2

Maximum (6, 102.2)

What is the extreme f(x)=-0.1x^2+1.2x+98.6 ?
The extreme f(x)=-0.1x^2+1.2x+98.6 is Maximum(6,102.2)