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midpoint
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inverse of f(x)=6log_{5}(2x-6)intercepts of f(x)=x^2+3x+3asymptotes of f(x)=(x^2-8x-20)/(15x-27)line (1,4),(2,4)range of f(x)=(x^2+6)/(x+3)
Frequently Asked Questions (FAQ)
What is the midpoint (-2,-2),(2,-8) ?
The midpoint (-2,-2),(2,-8) is (0,-5)