What is the perpendicular y=3x+1,(6,9) ?

The perpendicular y=3x+1,(6,9) is y=-1/3 x+11

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perpendicular y=3x+1,(6,9)

perpendicular

y = 3 x + 1, (6, 9)

y = - \frac{1}{3} x + 11

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x + 1

that passes through

(6, 9)

Find the slope of

y = 3 x + 1 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(6, 9) : y = - \frac{1}{3} x + 11

y = - \frac{1}{3} x + 11

What is the perpendicular y=3x+1,(6,9) ?
The perpendicular y=3x+1,(6,9) is y=-1/3 x+11