What is the inverse of (7x+2)/(x^2+x-2) ?

The inverse of (7x+2)/(x^2+x-2) is (-x+7+sqrt(9x^2-6x+49))/(2x),(-x+7-sqrt(9x^2-6x+49))/(2x)

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inverse of (7x+2)/(x^2+x-2)

inverse

\frac{7 x + 2}{x ^{2} + x - 2}

\frac{- x + 7 + 9 x ^{2} - 6 x + 49}{2 x}, \frac{- x + 7 - 9 x ^{2} - 6 x + 49}{2 x}

Solution steps

y = \frac{7 x + 2}{x ^{2} + x - 2}

Replace

x

with

y

x = \frac{7 y + 2}{y ^{2} + y - 2}

Solve for

y, x = \frac{7 y + 2}{y ^{2} + y - 2}

\frac{- x + 7 + 9 x ^{2} - 6 x + 49}{2 x}, \frac{- x + 7 - 9 x ^{2} - 6 x + 49}{2 x}

What is the inverse of (7x+2)/(x^2+x-2) ?
The inverse of (7x+2)/(x^2+x-2) is (-x+7+sqrt(9x^2-6x+49))/(2x),(-x+7-sqrt(9x^2-6x+49))/(2x)