What is the domain of f(x)=(sqrt(x-8))/(x(x-9)) ?

The domain of f(x)=(sqrt(x-8))/(x(x-9)) is 8 9

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domain of f(x)=(sqrt(x-8))/(x(x-9))

domain

f (x) = \frac{x - 8}{x ( x - 9 )}

8 \leq x < 9 or x > 9

Interval Notation

[8, 9) \cup (9, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 8

Find undefined (singularity) points:

x = 0, x = 9

Combine real regions and undefined points for final function domain

8 \leq x < 9 or x > 9

What is the domain of f(x)=(sqrt(x-8))/(x(x-9)) ?
The domain of f(x)=(sqrt(x-8))/(x(x-9)) is 8<= x<9\lor x>9