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midpoint
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domain of x^2-4x+4range of f(x)=2x^2+8xdomain of (\sqrt[3]{x-9})/(x^3-9)inverse of f(x)=\sqrt[3]{(3x-4)/2}+1asymptotes of f(x)=(3x-3)/(x^2-1)
Frequently Asked Questions (FAQ)
What is the midpoint (4,-1),(-5,9) ?
The midpoint (4,-1),(-5,9) is (-1/2 ,4)