What is the domain of (sqrt(x+4))/(x^2-9) ?

The domain of (sqrt(x+4))/(x^2-9) is -4 3

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domain of (sqrt(x+4))/(x^2-9)

domain

\frac{x + 4}{x ^{2} - 9}

- 4 \leq x < - 3 or - 3 < x < 3 or x > 3

Interval Notation

[- 4, - 3) \cup (- 3, 3) \cup (3, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

Find undefined (singularity) points:

x = 3, x = - 3

Combine real regions and undefined points for final function domain

- 4 \leq x < - 3 or - 3 < x < 3 or x > 3

What is the domain of (sqrt(x+4))/(x^2-9) ?
The domain of (sqrt(x+4))/(x^2-9) is -4<= x<-3\lor-3<x<3\lor x>3