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midpoint
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inverse of log_{10}(x)inverse of f(x)=(8x)/(x^2+49)extreme f(x)=(x^2-9)^2inverse of f(x)= 8/(x-1)perpendicular y=4x+8,(4,-1)
Frequently Asked Questions (FAQ)
What is the midpoint (3,7),(-8,-10) ?
The midpoint (3,7),(-8,-10) is (-5/2 ,-3/2)