What is the domain of f(x)= 1/((1-x^2)^{1/2)-1} ?

The domain of f(x)= 1/((1-x^2)^{1/2)-1} is -1<= x<0\lor 0<x<= 1

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domain of f(x)= 1/((1-x^2)^{1/2)-1}

domain

f (x) = \frac{1}{( 1 - x ^{2} ) ^{\frac{1}{2}} - 1}

- 1 \leq x < 0 or 0 < x \leq 1

Interval Notation

[- 1, 0) \cup (0, 1]

Solution steps

Find non-negative values for radicals:

- 1 \leq x \leq 1

Find undefined (singularity) points:

x = 0

Combine real regions and undefined points for final function domain

- 1 \leq x < 0 or 0 < x \leq 1

What is the domain of f(x)= 1/((1-x^2)^{1/2)-1} ?
The domain of f(x)= 1/((1-x^2)^{1/2)-1} is -1<= x<0\lor 0<x<= 1