extreme f(x)=310x^3-x^2-8x+48

Lösung

extrempunkte

f (x) = 310 x^{3} - x^{2} - 8 x + 48

Maximum (\frac{1 - 7441}{930}, \frac{7441 7441 - 11161}{1297350} + 48), Minimum (\frac{1 + 7441}{930}, \frac{- 11161 - 7441 7441}{1297350} + 48)

Schritte zur Lösung

f^{'} (x) = 930 x^{2} - 2 x - 8

Intervalle finden:

Ansteigend

: - \infty < x < \frac{- 7441 + 1}{930},

Absteigend

: \frac{- 7441 + 1}{930} < x < \frac{7441 + 1}{930},

Ansteigend

: \frac{7441 + 1}{930} < x < \infty

Stecke

x = \frac{1 - 7441}{930}

310 x^{3} - x^{2} - 8 x + 48 : \frac{7441 7441 - 11161}{1297350} + 48

Maximum (\frac{1 - 7441}{930}, \frac{7441 7441 - 11161}{1297350} + 48)

Stecke

x = \frac{1 + 7441}{930}

310 x^{3} - x^{2} - 8 x + 48 : \frac{- 11161 - 7441 7441}{1297350} + 48

Minimum (\frac{1 + 7441}{930}, \frac{- 11161 - 7441 7441}{1297350} + 48)

Maximum (\frac{1 - 7441}{930}, \frac{7441 7441 - 11161}{1297350} + 48), Minimum (\frac{1 + 7441}{930}, \frac{- 11161 - 7441 7441}{1297350} + 48)

in v erse f (x) = x^{2} - 10 x

cr i t i c a l f (x) = 2 x + 5 cos (x)

in v erse f (x) = 3 + x^{3}

d o main f (x) = \frac{x + 1}{x ^{2} - 3 x + 2}

p a r a ll e l 7 x + 3 y = 9