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midpoint
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symmetry y=x^2-8x+12inverse of f(x)=4x^3+7range of ln(x)+2range of f(x)=(x^2-2x-3)/(x+2)critical (3x)/(4-x^2)
Frequently Asked Questions (FAQ)
What is the midpoint (-1,-1),(-7,-9) ?
The midpoint (-1,-1),(-7,-9) is (-4,-5)