What is the critical y=(9x-12)/(5x^{1/5)} ?

The critical y=(9x-12)/(5x^{1/5)} is x=-1/3

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critical y=(9x-12)/(5x^{1/5)}

critical points

y = \frac{9 x - 12}{5 x ^{\frac{1}{5}}}

x = - \frac{1}{3}

Solution steps

\frac{9 x - 12}{5 x ^{\frac{1}{5}}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{1}{3}, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{9 x - 12}{5 x ^{\frac{1}{5}}} : x < 0 or x > 0

\frac{9 x - 12}{5 x ^{\frac{1}{5}}}

is not defined at

x = 0

, therefore:

x = - \frac{1}{3}

What is the critical y=(9x-12)/(5x^{1/5)} ?
The critical y=(9x-12)/(5x^{1/5)} is x=-1/3