What is the extreme f(x)=(x+2)^2(x-1) ?

The extreme f(x)=(x+2)^2(x-1) is Maximum(-2,0),Minimum(0,-4)

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extreme f(x)=(x+2)^2(x-1)

extreme points

f (x) = (x + 2)^{2} (x - 1)

Maximum (- 2, 0), Minimum (0, - 4)

Solution steps

f^{'} (x) = 3 x (x + 2)

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < \infty

Plug

x = - 2

into

(x + 2)^{2} (x - 1) : 0

Maximum (- 2, 0)

Plug

x = 0

into

(x + 2)^{2} (x - 1) : - 4

Minimum (0, - 4)

Maximum (- 2, 0), Minimum (0, - 4)

What is the extreme f(x)=(x+2)^2(x-1) ?
The extreme f(x)=(x+2)^2(x-1) is Maximum(-2,0),Minimum(0,-4)