What is the domain of f(x)=sqrt(x^2-16) ?

The domain of f(x)=sqrt(x^2-16) is x = 4

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domain of f(x)=sqrt(x^2-16)

domain

f (x) = x^{2} - 16

x \leq - 4 or x \geq 4

Interval Notation

(- \infty, - 4] \cup [4, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 4 or x \geq 4

The function domain

x \leq - 4 or x \geq 4

What is the domain of f(x)=sqrt(x^2-16) ?
The domain of f(x)=sqrt(x^2-16) is x<=-4\lor x>= 4